Have you noticed that some states are reporting massive voter turnout? In some places, the numbers are so high that they don’t even make sense.
Kim Strassel of the Wall Street Journal did a deep dive into the numbers in Wisconsin and they just aren’t realistic at all.
Here are the numbers:
Wisconsin has 3,684,726 active registered voters.
They counted 3,288,771 votes.
That's, um, a bit unbelievable.
89% turnout? Ok sure. 🙄
— HARLAN Z. HILL 🇺🇸 (@Harlan) November 4, 2020
This is what Kim Strassel said, via Thread Reader:
I am legitimately interested/confused by this. I checked, and the top number is indeed Wisconsin’s active registered voter number as of Nov. 1. The bottom is approx. what has been counted. That is a (not feasible) 89% turnout.
The Milwaukee Journal Sentinel is claiming a 71% state turnout. I’m not sure where it gets this, but that would make more sense, given even populous Milwaukee didn’t exceed 83% turnout, and Dane lower. (Do math on what rest of state wud need to bump up state avg to 89)
True, Wisconsin has same day voter registration. But to be at 71%, WI would have yesterday needed 900k same-day registrations. ( If I’m doing my math wrong–please tell me. 3,288,771 divided by 4,588,771 equals 71% . 4,588,771 minus 3,684,726 =900k)
Is that possible/conceivable? That would be akin to increasing WI’s registered voting population by up to 30%–in one day. It would also suggest that if those same-day registrations hadn’t happened, WI would have had a ridiculously LOW turnout.
This looks like fraud, plain and simple.
Wow. A 150,000 Biden vote to ZERO Trump vote ballot drop in Michigan this morning. Nothing to see in the dark overnight hours of #Election2020
Add this to the Wisconsin 200,000 Biden vote jump at 5am, & we have probable Voter Fraud. (see chart)#StopTheSteal https://t.co/jNw6A19UIw pic.twitter.com/T24WY8RmTp
— Capt TUCKER⚓ℹFollows Back (@CaptnJabberJaws) November 4, 2020
This demands an investigation and recount.